It works more general for all the rationals.
Take it easy comrade, I'm aware
I think it is true that any subset of the rationals gives a box counting dimension \leq 1
It (subset of rationals) actually does.
The main point is that the Hausdorf dimension is zero. Because it is countable. Thefore, the Hausdorf dimension says it is not a fractal whereas the Boxcounting dimensions says it is a fractal.
I think I get where you are coming from.
It's nice learning from you anyways, thanks.
I am happy to share :3
Ah yes, this is obviously true :P
An interesting exercise would be to construct a non-finite subset of the rationals with box counting dimension equal to zero :3
Ok, good luck with that.